412 lines
16 KiB
Java
412 lines
16 KiB
Java
/*
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* Copyright (C) 2012 The Android Open Source Project
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*
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* Licensed under the Apache License, Version 2.0 (the "License");
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* you may not use this file except in compliance with the License.
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* You may obtain a copy of the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing, software
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* distributed under the License is distributed on an "AS IS" BASIS,
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* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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* See the License for the specific language governing permissions and
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* limitations under the License.
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*/
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package com.android.inputmethod.latin.utils;
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import android.text.TextUtils;
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import com.android.inputmethod.annotations.UsedForTesting;
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import com.android.inputmethod.latin.Constants;
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import java.util.ArrayList;
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import java.util.Locale;
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public final class StringUtils {
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private static final String TAG = StringUtils.class.getSimpleName();
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public static final int CAPITALIZE_NONE = 0; // No caps, or mixed case
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public static final int CAPITALIZE_FIRST = 1; // First only
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public static final int CAPITALIZE_ALL = 2; // All caps
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private static final String EMPTY_STRING = "";
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private StringUtils() {
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// This utility class is not publicly instantiable.
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}
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public static int codePointCount(final String text) {
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if (TextUtils.isEmpty(text)) return 0;
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return text.codePointCount(0, text.length());
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}
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public static String newSingleCodePointString(int codePoint) {
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if (Character.charCount(codePoint) == 1) {
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// Optimization: avoid creating an temporary array for characters that are
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// represented by a single char value
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return String.valueOf((char) codePoint);
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}
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// For surrogate pair
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return new String(Character.toChars(codePoint));
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}
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public static boolean containsInArray(final String text, final String[] array) {
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for (final String element : array) {
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if (text.equals(element)) return true;
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}
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return false;
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}
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/**
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* Comma-Splittable Text is similar to Comma-Separated Values (CSV) but has much simpler syntax.
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* Unlike CSV, Comma-Splittable Text has no escaping mechanism, so that the text can't contain
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* a comma character in it.
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*/
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private static final String SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT = ",";
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public static boolean containsInCommaSplittableText(final String text,
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final String extraValues) {
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if (TextUtils.isEmpty(extraValues)) {
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return false;
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}
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return containsInArray(text, extraValues.split(SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT));
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}
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public static String joinCommaSplittableText(final String head, final String tail) {
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if (TextUtils.isEmpty(head) && TextUtils.isEmpty(tail)) {
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return EMPTY_STRING;
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}
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// Here either head or tail is not null.
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if (TextUtils.isEmpty(head)) {
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return tail;
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}
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if (TextUtils.isEmpty(tail)) {
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return head;
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}
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return head + SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT + tail;
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}
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public static String appendToCommaSplittableTextIfNotExists(final String text,
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final String extraValues) {
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if (TextUtils.isEmpty(extraValues)) {
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return text;
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}
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if (containsInCommaSplittableText(text, extraValues)) {
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return extraValues;
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}
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return extraValues + SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT + text;
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}
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public static String removeFromCommaSplittableTextIfExists(final String text,
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final String extraValues) {
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if (TextUtils.isEmpty(extraValues)) {
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return EMPTY_STRING;
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}
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final String[] elements = extraValues.split(SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT);
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if (!containsInArray(text, elements)) {
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return extraValues;
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}
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final ArrayList<String> result = CollectionUtils.newArrayList(elements.length - 1);
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for (final String element : elements) {
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if (!text.equals(element)) {
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result.add(element);
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}
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}
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return TextUtils.join(SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT, result);
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}
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/**
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* Remove duplicates from an array of strings.
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*
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* This method will always keep the first occurrence of all strings at their position
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* in the array, removing the subsequent ones.
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*/
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public static void removeDupes(final ArrayList<String> suggestions) {
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if (suggestions.size() < 2) return;
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int i = 1;
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// Don't cache suggestions.size(), since we may be removing items
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while (i < suggestions.size()) {
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final String cur = suggestions.get(i);
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// Compare each suggestion with each previous suggestion
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for (int j = 0; j < i; j++) {
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final String previous = suggestions.get(j);
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if (TextUtils.equals(cur, previous)) {
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suggestions.remove(i);
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i--;
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break;
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}
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}
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i++;
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}
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}
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public static String capitalizeFirstCodePoint(final String s, final Locale locale) {
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if (s.length() <= 1) {
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return s.toUpperCase(locale);
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}
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// Please refer to the comment below in
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// {@link #capitalizeFirstAndDowncaseRest(String,Locale)} as this has the same shortcomings
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final int cutoff = s.offsetByCodePoints(0, 1);
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return s.substring(0, cutoff).toUpperCase(locale) + s.substring(cutoff);
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}
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public static String capitalizeFirstAndDowncaseRest(final String s, final Locale locale) {
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if (s.length() <= 1) {
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return s.toUpperCase(locale);
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}
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// TODO: fix the bugs below
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// - This does not work for Greek, because it returns upper case instead of title case.
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// - It does not work for Serbian, because it fails to account for the "lj" character,
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// which should be "Lj" in title case and "LJ" in upper case.
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// - It does not work for Dutch, because it fails to account for the "ij" digraph when it's
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// written as two separate code points. They are two different characters but both should
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// be capitalized as "IJ" as if they were a single letter in most words (not all). If the
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// unicode char for the ligature is used however, it works.
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final int cutoff = s.offsetByCodePoints(0, 1);
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return s.substring(0, cutoff).toUpperCase(locale) + s.substring(cutoff).toLowerCase(locale);
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}
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private static final int[] EMPTY_CODEPOINTS = {};
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public static int[] toCodePointArray(final String string) {
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final int length = string.length();
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if (length <= 0) {
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return EMPTY_CODEPOINTS;
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}
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final int[] codePoints = new int[string.codePointCount(0, length)];
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int destIndex = 0;
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for (int index = 0; index < length; index = string.offsetByCodePoints(index, 1)) {
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codePoints[destIndex] = string.codePointAt(index);
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destIndex++;
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}
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return codePoints;
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}
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// This method assumes the text is not null. For the empty string, it returns CAPITALIZE_NONE.
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public static int getCapitalizationType(final String text) {
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// If the first char is not uppercase, then the word is either all lower case or
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// camel case, and in either case we return CAPITALIZE_NONE.
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final int len = text.length();
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int index = 0;
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for (; index < len; index = text.offsetByCodePoints(index, 1)) {
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if (Character.isLetter(text.codePointAt(index))) {
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break;
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}
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}
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if (index == len) return CAPITALIZE_NONE;
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if (!Character.isUpperCase(text.codePointAt(index))) {
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return CAPITALIZE_NONE;
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}
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int capsCount = 1;
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int letterCount = 1;
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for (index = text.offsetByCodePoints(index, 1); index < len;
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index = text.offsetByCodePoints(index, 1)) {
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if (1 != capsCount && letterCount != capsCount) break;
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final int codePoint = text.codePointAt(index);
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if (Character.isUpperCase(codePoint)) {
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++capsCount;
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++letterCount;
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} else if (Character.isLetter(codePoint)) {
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// We need to discount non-letters since they may not be upper-case, but may
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// still be part of a word (e.g. single quote or dash, as in "IT'S" or "FULL-TIME")
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++letterCount;
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}
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}
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// We know the first char is upper case. So we want to test if either every letter other
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// than the first is lower case, or if they are all upper case. If the string is exactly
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// one char long, then we will arrive here with letterCount 1, and this is correct, too.
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if (1 == capsCount) return CAPITALIZE_FIRST;
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return (letterCount == capsCount ? CAPITALIZE_ALL : CAPITALIZE_NONE);
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}
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public static boolean isIdenticalAfterUpcase(final String text) {
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final int length = text.length();
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int i = 0;
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while (i < length) {
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final int codePoint = text.codePointAt(i);
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if (Character.isLetter(codePoint) && !Character.isUpperCase(codePoint)) {
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return false;
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}
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i += Character.charCount(codePoint);
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}
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return true;
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}
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public static boolean isIdenticalAfterDowncase(final String text) {
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final int length = text.length();
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int i = 0;
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while (i < length) {
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final int codePoint = text.codePointAt(i);
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if (Character.isLetter(codePoint) && !Character.isLowerCase(codePoint)) {
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return false;
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}
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i += Character.charCount(codePoint);
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}
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return true;
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}
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/**
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* Returns true if all code points in text are whitespace, false otherwise. Empty is true.
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*/
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// Interestingly enough, U+00A0 NO-BREAK SPACE and U+200B ZERO-WIDTH SPACE are not considered
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// whitespace, while EN SPACE, EM SPACE and IDEOGRAPHIC SPACES are.
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public static boolean containsOnlyWhitespace(final String text) {
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final int length = text.length();
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int i = 0;
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while (i < length) {
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final int codePoint = text.codePointAt(i);
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if (!Character.isWhitespace(codePoint)) {
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return false;
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}
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i += Character.charCount(codePoint);
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}
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return true;
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}
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public static boolean isIdenticalAfterCapitalizeEachWord(final String text,
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final String separators) {
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boolean needCapsNext = true;
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final int len = text.length();
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for (int i = 0; i < len; i = text.offsetByCodePoints(i, 1)) {
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final int codePoint = text.codePointAt(i);
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if (Character.isLetter(codePoint)) {
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if ((needCapsNext && !Character.isUpperCase(codePoint))
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|| (!needCapsNext && !Character.isLowerCase(codePoint))) {
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return false;
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}
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}
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// We need a capital letter next if this is a separator.
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needCapsNext = (-1 != separators.indexOf(codePoint));
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}
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return true;
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}
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// TODO: like capitalizeFirst*, this does not work perfectly for Dutch because of the IJ digraph
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// which should be capitalized together in *some* cases.
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public static String capitalizeEachWord(final String text, final String separators,
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final Locale locale) {
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final StringBuilder builder = new StringBuilder();
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boolean needCapsNext = true;
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final int len = text.length();
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for (int i = 0; i < len; i = text.offsetByCodePoints(i, 1)) {
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final String nextChar = text.substring(i, text.offsetByCodePoints(i, 1));
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if (needCapsNext) {
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builder.append(nextChar.toUpperCase(locale));
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} else {
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builder.append(nextChar.toLowerCase(locale));
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}
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// We need a capital letter next if this is a separator.
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needCapsNext = (-1 != separators.indexOf(nextChar.codePointAt(0)));
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}
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return builder.toString();
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}
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/**
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* Approximates whether the text before the cursor looks like a URL.
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*
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* This is not foolproof, but it should work well in the practice.
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* Essentially it walks backward from the cursor until it finds something that's not a letter,
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* digit, or common URL symbol like underscore. If it hasn't found a period yet, then it
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* does not look like a URL.
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* If the text:
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* - starts with www and contains a period
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* - starts with a slash preceded by either a slash, whitespace, or start-of-string
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* Then it looks like a URL and we return true. Otherwise, we return false.
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*
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* Note: this method is called quite often, and should be fast.
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*
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* TODO: This will return that "abc./def" and ".abc/def" look like URLs to keep down the
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* code complexity, but ideally it should not. It's acceptable for now.
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*/
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public static boolean lastPartLooksLikeURL(final CharSequence text) {
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int i = text.length();
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if (0 == i) return false;
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int wCount = 0;
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int slashCount = 0;
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boolean hasSlash = false;
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boolean hasPeriod = false;
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int codePoint = 0;
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while (i > 0) {
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codePoint = Character.codePointBefore(text, i);
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if (codePoint < Constants.CODE_PERIOD || codePoint > 'z') {
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// Handwavy heuristic to see if that's a URL character. Anything between period
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// and z. This includes all lower- and upper-case ascii letters, period,
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// underscore, arrobase, question mark, equal sign. It excludes spaces, exclamation
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// marks, double quotes...
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// Anything that's not a URL-like character causes us to break from here and
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// evaluate normally.
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break;
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}
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if (Constants.CODE_PERIOD == codePoint) {
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hasPeriod = true;
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}
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if (Constants.CODE_SLASH == codePoint) {
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hasSlash = true;
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if (2 == ++slashCount) {
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return true;
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}
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} else {
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slashCount = 0;
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}
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if ('w' == codePoint) {
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++wCount;
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} else {
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wCount = 0;
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}
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i = Character.offsetByCodePoints(text, i, -1);
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}
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// End of the text run.
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// If it starts with www and includes a period, then it looks like a URL.
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if (wCount >= 3 && hasPeriod) return true;
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// If it starts with a slash, and the code point before is whitespace, it looks like an URL.
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if (1 == slashCount && (0 == i || Character.isWhitespace(codePoint))) return true;
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// If it has both a period and a slash, it looks like an URL.
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if (hasPeriod && hasSlash) return true;
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// Otherwise, it doesn't look like an URL.
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return false;
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}
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public static boolean isEmptyStringOrWhiteSpaces(final String s) {
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final int N = codePointCount(s);
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for (int i = 0; i < N; ++i) {
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if (!Character.isWhitespace(s.codePointAt(i))) {
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return false;
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}
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}
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return true;
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}
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@UsedForTesting
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public static String byteArrayToHexString(final byte[] bytes) {
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if (bytes == null || bytes.length == 0) {
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return EMPTY_STRING;
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}
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final StringBuilder sb = new StringBuilder();
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for (byte b : bytes) {
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sb.append(String.format("%02x", b & 0xff));
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}
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return sb.toString();
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}
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/**
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* Convert hex string to byte array. The string length must be an even number.
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*/
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@UsedForTesting
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public static byte[] hexStringToByteArray(final String hexString) {
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if (TextUtils.isEmpty(hexString)) {
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return null;
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}
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final int N = hexString.length();
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if (N % 2 != 0) {
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throw new NumberFormatException("Input hex string length must be an even number."
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+ " Length = " + N);
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}
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final byte[] bytes = new byte[N / 2];
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for (int i = 0; i < N; i += 2) {
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bytes[i / 2] = (byte) ((Character.digit(hexString.charAt(i), 16) << 4)
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+ Character.digit(hexString.charAt(i + 1), 16));
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}
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return bytes;
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}
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}
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