55 lines
1.8 KiB
Java
55 lines
1.8 KiB
Java
/*
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* Copyright (C) 2011 The Android Open Source Project
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*
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* Licensed under the Apache License, Version 2.0 (the "License");
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* you may not use this file except in compliance with the License.
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* You may obtain a copy of the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing, software
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* distributed under the License is distributed on an "AS IS" BASIS,
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* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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* See the License for the specific language governing permissions and
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* limitations under the License.
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*/
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package com.android.inputmethod.latin.makedict;
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import com.android.inputmethod.latin.makedict.FusionDictionary.Node;
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import java.util.ArrayList;
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import junit.framework.TestCase;
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/**
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* Unit tests for BinaryDictInputOutput.
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*/
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public class BinaryDictInputOutputTest extends TestCase {
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public void setUp() throws Exception {
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super.setUp();
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}
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public void tearDown() throws Exception {
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super.tearDown();
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}
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// Test the flattened array contains the expected number of nodes, and
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// that it does not contain any duplicates.
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public void testFlattenNodes() {
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final FusionDictionary dict = new FusionDictionary();
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dict.add("foo", 1, null, null);
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dict.add("fta", 1, null, null);
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dict.add("ftb", 1, null, null);
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dict.add("bar", 1, null, null);
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dict.add("fool", 1, null, null);
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final ArrayList<Node> result = BinaryDictInputOutput.flattenTree(dict.mRoot);
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assertEquals(4, result.size());
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while (!result.isEmpty()) {
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final Node n = result.remove(0);
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assertFalse("Flattened array contained the same node twice", result.contains(n));
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}
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}
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}
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