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Check user dictionary before inserting new word

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Bug: 3264920
Change-Id: I9fe45a61b2ad2b1ed69d3a0cbc6eebecb4038acc
This commit is contained in:
Tadashi G. Takaoka 2010-12-13 11:37:28 +09:00
parent 9ecad8c2e8
commit c5f1368090
1 changed files with 18 additions and 2 deletions
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20
java/src/com/android/inputmethod/latin/UserDictionary.java
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@ -21,6 +21,7 @@ import android.content.ContentValues;
import android.content.Context;
import android.database.ContentObserver;
import android.database.Cursor;
import android.net.Uri;
import android.provider.UserDictionary.Words;
public class UserDictionary extends ExpandableDictionary {
@ -80,7 +81,7 @@ public class UserDictionary extends ExpandableDictionary {
* @TODO use a higher or float range for frequency
*/
@Override
public synchronized void addWord(String word, int frequency) {
public synchronized void addWord(final String word, final int frequency) {
// Force load the dictionary here synchronously
if (getRequiresReload()) loadDictionaryAsync();
// Safeguard against adding long words. Can cause stack overflow.
@ -99,7 +100,22 @@ public class UserDictionary extends ExpandableDictionary {
new Thread("addWord") {
@Override
public void run() {
contentResolver.insert(Words.CONTENT_URI, values);
Cursor cursor = contentResolver.query(Words.CONTENT_URI, PROJECTION,
"word=? and ((locale IS NULL) or (locale=?))",
new String[] { word, mLocale }, null);
if (cursor != null && cursor.moveToFirst()) {
String locale = cursor.getString(cursor.getColumnIndex(Words.LOCALE));
// If locale is null, we will not override the entry.
if (locale != null && locale.equals(mLocale.toString())) {
long id = cursor.getLong(cursor.getColumnIndex(Words._ID));
Uri uri = Uri.withAppendedPath(Words.CONTENT_URI, Long.toString(id));
// Update the entry with new frequency value.
contentResolver.update(uri, values, null, null);
}
} else {
// Insert new entry.
contentResolver.insert(Words.CONTENT_URI, values);
}
}
}.start();