Remove a duplicate processing (A5)

This filtering is already done in native code. It's useless (and
costly) to do it again here.

Change-Id: Ide6794d7a8682a881f097f33e222f10d30f297bd
main
Jean Chalard 2012-06-26 14:41:30 +09:00
parent fac8a16c6f
commit 5e0545d69d
1 changed files with 4 additions and 25 deletions

View File

@ -273,33 +273,12 @@ public class Suggest implements Dictionary.WordCallback {
if (!TextUtils.isEmpty(prevWordForBigram)) {
getAllBigrams(prevWordForBigram, wordComposer);
if (TextUtils.isEmpty(consideredWord)) {
// Nothing entered: return all bigrams for the previous word
int insertCount = Math.min(mBigramSuggestions.size(), MAX_SUGGESTIONS);
for (int i = 0; i < insertCount; ++i) {
addBigramToSuggestions(mBigramSuggestions.get(i));
}
} else {
// Word entered: return only bigrams that match the first char of the typed word
final char currentChar = consideredWord.charAt(0);
// TODO: Must pay attention to locale when changing case.
// TODO: Use codepoint instead of char
final char currentCharUpper = Character.toUpperCase(currentChar);
int count = 0;
final int bigramSuggestionSize = mBigramSuggestions.size();
for (int i = 0; i < bigramSuggestionSize; i++) {
final SuggestedWordInfo bigramSuggestion = mBigramSuggestions.get(i);
final char bigramSuggestionFirstChar =
(char)bigramSuggestion.codePointAt(0);
if (bigramSuggestionFirstChar == currentChar
|| bigramSuggestionFirstChar == currentCharUpper) {
addBigramToSuggestions(bigramSuggestion);
if (++count > MAX_SUGGESTIONS) break;
}
}
// Nothing entered: return all bigrams for the previous word
int insertCount = Math.min(mBigramSuggestions.size(), MAX_SUGGESTIONS);
for (int i = 0; i < insertCount; ++i) {
addBigramToSuggestions(mBigramSuggestions.get(i));
}
}
} else if (wordComposer.size() > 1) {
final WordComposer wordComposerForLookup;
if (mTrailingSingleQuotesCount > 0) {