Remove useless code (A63)

If the separator is not a space, then we will always call
setPunctuationSuggestions and reset the suggestion strip anyway.
If the separator is a space, then the cursor has a space on
the left, which means isCursorTouchingWord depends only on
whether it touches a word on the right. If we were displaying
the "add to dictionary hint", it means a suggestion was just
chosen, so it had to be displayed, and that requires a composing
word and no non-separator at the right of the cursor.

In the end, if we go through this postUpdateSuggestions call,
we are sure we will reset the suggestions later in this method,
either by calling postUpdateBigramPredictions, or
setPunctuationSuggestions.

Change-Id: I95d5f77a5d0ac6d1a6ced8d67d6ac8f650db4a32
This commit is contained in:
Jean Chalard 2012-07-05 14:18:43 +09:00
parent 8ba33c1a49
commit 43193ad60f

View file

@ -1534,11 +1534,6 @@ public class LatinIME extends InputMethodService implements KeyboardActionListen
// Returns true if we did an autocorrection, false otherwise. // Returns true if we did an autocorrection, false otherwise.
private boolean handleSeparator(final int primaryCode, final int x, final int y, private boolean handleSeparator(final int primaryCode, final int x, final int y,
final int spaceState) { final int spaceState) {
// Should dismiss the "Touch again to save" message when handling separator
if (mSuggestionsView != null && mSuggestionsView.dismissAddToDictionaryHint()) {
mHandler.postUpdateSuggestions();
}
boolean didAutoCorrect = false; boolean didAutoCorrect = false;
// Handle separator // Handle separator
if (mWordComposer.isComposingWord()) { if (mWordComposer.isComposingWord()) {