Simplify a call, and add comments (A2)
Since the function has to be modified heavily but does a lot of non-trivial work, add a wealth of comments explaining what it does and why so as to facilitate understanding the changes to come. Bug: 4967874 Change-Id: I6c21aea15f161d807035f279dfb7d1b98b3e9144
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2 changed files with 67 additions and 18 deletions
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@ -204,8 +204,7 @@ public class RichInputConnection {
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}
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// This never calls InputConnection#getCapsMode - in fact, it's a static method that
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// never blocks or initiates IPC.
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return StringUtils.getCapsMode(mCommittedTextBeforeComposingText,
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mCommittedTextBeforeComposingText.length(), inputType);
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return StringUtils.getCapsMode(mCommittedTextBeforeComposingText, inputType);
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}
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public CharSequence getTextBeforeCursor(final int i, final int j) {
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@ -208,7 +208,6 @@ public final class StringUtils {
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* issues). This will change in the future as we simplify the code for our use and fix bugs.
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*
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* @param cs The text that should be checked for caps modes.
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* @param off Location in the text at which to check.
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* @param reqModes The modes to be checked: may be any combination of
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* {@link #CAP_MODE_CHARACTERS}, {@link #CAP_MODE_WORDS}, and
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* {@link #CAP_MODE_SENTENCES}.
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@ -218,52 +217,93 @@ public final class StringUtils {
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* {@link #CAP_MODE_CHARACTERS}, {@link #CAP_MODE_WORDS}, and
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* {@link #CAP_MODE_SENTENCES}.
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*/
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public static int getCapsMode(CharSequence cs, int off, int reqModes) {
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if (off < 0) {
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return 0;
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}
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public static int getCapsMode(CharSequence cs, int reqModes) {
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int i;
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char c;
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int mode = 0;
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// Quick description of what we want to do:
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// CAP_MODE_CHARACTERS is always on.
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// CAP_MODE_WORDS is on if there is some whitespace before the cursor.
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// CAP_MODE_SENTENCES is on if there is some whitespace before the cursor, and the end
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// of a sentence just before that.
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// We ignore opening parentheses and the like just before the cursor for purposes of
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// finding whitespace for WORDS and SENTENCES modes.
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// The end of a sentence ends with a period, question mark or exclamation mark. If it's
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// a period, it also needs not to be an abbreviation, which means it also needs to either
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// be immediately preceded by punctuation, or by a string of only letters with single
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// periods interleaved.
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// Step 1 : check for cap mode characters. If it's looked for, it's always on.
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if ((reqModes & TextUtils.CAP_MODE_CHARACTERS) != 0) {
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mode |= TextUtils.CAP_MODE_CHARACTERS;
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}
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if ((reqModes & (TextUtils.CAP_MODE_WORDS | TextUtils.CAP_MODE_SENTENCES)) == 0) {
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// Here we are not looking for words or sentences modes, so since we already evaluated
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// mode characters, we can return.
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return mode;
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}
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// Back over allowed opening punctuation.
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for (i = off; i > 0; i--) {
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// Step 2 : Skip (ignore at the end of input) any opening punctuation. This includes
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// opening parentheses, brackets, opening quotes, everything that *opens* a span of
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// text in the linguistic sense. In RTL languages, this is still an opening sign, although
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// it may look like a right parenthesis for example. We also include double quote and
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// single quote since they aren't start punctuation in the unicode sense, but should still
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// be skipped for English. TODO: does this depend on the language?
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for (i = cs.length(); i > 0; i--) {
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c = cs.charAt(i - 1);
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if (c != '"' && c != '\'' && Character.getType(c) != Character.START_PUNCTUATION) {
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break;
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}
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}
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// Start of paragraph, with optional whitespace.
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// We are now on the character that precedes any starting punctuation, so in the most
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// frequent case this will be whitespace or a letter, although it may occasionally be a
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// start of line, or some symbol.
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// Step 3 : Search for the start of a paragraph. From the starting point computed in step 2,
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// we go back over any space or tab char sitting there. We find the start of a paragraph
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// if the first char that's not a space or tab is a start of line (as in, either \n or
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// start of text).
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int j = i;
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while (j > 0 && ((c = cs.charAt(j - 1)) == ' ' || c == '\t')) {
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j--;
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}
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if (j == 0 || cs.charAt(j - 1) == '\n') {
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// Here we know we are at the start of a paragraph, so we turn on word mode.
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// Note: I think this is entirely buggy. It will return mode words even if the app
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// didn't request it, and it will fail to return sentence mode even if this is actually
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// the start of a sentence. As it happens, Latin IME client code considers that mode
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// word *implies* mode sentence and tests for non-zeroness, so it happens to work.
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return mode | TextUtils.CAP_MODE_WORDS;
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}
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// Or start of word if we are that style.
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if ((reqModes & TextUtils.CAP_MODE_SENTENCES) == 0) {
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// If we don't have to check for mode sentence, then we know all we need to know
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// already. Either we have whitespace immediately before index i and we are at the
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// start of a word, or we don't and we aren't. But we just went over any whitespace
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// just before i and in fact j points before any whitespace, so if i != j that means
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// there is such whitespace. In this case, we have mode words.
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if (i != j) mode |= TextUtils.CAP_MODE_WORDS;
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return mode;
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}
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// There must be a space if not the start of paragraph.
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if (i == j) {
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// Finally, if we don't have whitespace before index i, it means neither mode words
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// nor mode sentences should be on so we can return right away.
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return mode;
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}
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// Please note that because of the reqModes & CAP_MODE_SENTENCES test a few lines above,
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// we know that mode sentences is being requested.
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// Back over allowed closing punctuation.
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// Step 4 : Search for sentence mode.
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for (; j > 0; j--) {
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// Here we look to go over any closing punctuation. This is because in dominant variants
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// of English, the final period is placed within double quotes and maybe other closing
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// punctuation signs.
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// TODO: this is wrong for almost everything except American typography rules for
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// English. It's wrong for British typography rules for English, it's wrong for French,
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// it's wrong for German, it's wrong for Spanish, and possibly everything else.
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// (note that American rules and British rules have nothing to do with en_US and en_GB,
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// as both rules are used in both countries - it's merely a name for the set of rules)
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c = cs.charAt(j - 1);
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if (c != '"' && c != '\'' && Character.getType(c) != Character.END_PUNCTUATION) {
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break;
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@ -273,8 +313,18 @@ public final class StringUtils {
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if (j > 0) {
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c = cs.charAt(j - 1);
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if (c == '.' || c == '?' || c == '!') {
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// Do not capitalize if the word ends with a period but
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// also contains a period, in which case it is an abbreviation.
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// Here we found a marker for sentence end (we consider these to be one of
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// either . or ? or ! only). So this is probably the end of a sentence, but if we
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// found a period, we still want to check the case where this is a abbreviation
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// period rather than a full stop. To do this, we look for a period within a word
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// before the period we just found; if any, we take that to mean it was an
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// abbreviation.
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// A typical example of the above is "In the U.S. ", where the last period is
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// not a full stop and we should not capitalize.
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// TODO: the rule below is broken. In particular it fails for runs of periods,
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// whatever the reason. In the example "in the U.S..", the last period is a full
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// stop following the abbreviation period, and we should capitalize but we don't.
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// Likewise, "I don't know... " should capitalize, but fails to do so.
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if (c == '.') {
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for (int k = j - 2; k >= 0; k--) {
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c = cs.charAt(k);
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