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[SD6] Inline a constant and remove logic become useless 

Bug: 15840116
Change-Id: I04b9d6bd45d9e806c268fa8ecb4653f8af729095
Jean Chalard 2014-06-27 22:01:51 +09:00
parent 1d30023961
commit 2a5824a63b
1 changed files with 8 additions and 21 deletions
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29
java/src/com/android/inputmethod/latin/RichInputConnection.java
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@ -626,7 +626,6 @@ public final class RichInputConnection {
* @return a range containing the text surrounding the cursor
*/
public TextRange getWordRangeAtCursor(final int[] sortedSeparators) {
final int additionalPrecedingWordsCount = 0;
mIC = mParent.getCurrentInputConnection();
if (mIC == null) {
return null;
@ -639,29 +638,17 @@ public final class RichInputConnection {
return null;
}
// Going backward, alternate skipping non-separators and separators until enough words
// have been read.
int count = additionalPrecedingWordsCount;
// Going backward, find the first breaking point (separator)
int startIndexInBefore = before.length();
boolean isStoppingAtWhitespace = true; // toggles to indicate what to stop at
while (true) { // see comments below for why this is guaranteed to halt
while (startIndexInBefore > 0) {
final int codePoint = Character.codePointBefore(before, startIndexInBefore);
if (isStoppingAtWhitespace == isSeparator(codePoint, sortedSeparators)) {
break; // inner loop
}
while (startIndexInBefore > 0) {
final int codePoint = Character.codePointBefore(before, startIndexInBefore);
if (isSeparator(codePoint, sortedSeparators)) {
break;
}
--startIndexInBefore;
if (Character.isSupplementaryCodePoint(codePoint)) {
--startIndexInBefore;
if (Character.isSupplementaryCodePoint(codePoint)) {
--startIndexInBefore;
}
}
// isStoppingAtWhitespace is true every other time through the loop,
// so additionalPrecedingWordsCount is guaranteed to become < 0, which
// guarantees outer loop termination
if (isStoppingAtWhitespace && (--count < 0)) {
break; // outer loop
}
isStoppingAtWhitespace = !isStoppingAtWhitespace;
}
// Find last word separator after the cursor