66 lines
1.9 KiB
Java
66 lines
1.9 KiB
Java
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/*
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* Copyright (C) 2011 The Android Open Source Project
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*
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* Licensed under the Apache License, Version 2.0 (the "License"); you may not
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* use this file except in compliance with the License. You may obtain a copy of
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* the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing, software
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* distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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* WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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* License for the specific language governing permissions and limitations under
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* the License.
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*/
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package com.android.inputmethod.latin;
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import com.android.inputmethod.latin.FusionDictionary.WeightedString;
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import java.util.ArrayList;
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/**
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* Utility class for a word with a frequency.
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*
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* This is chiefly used to iterate a dictionary.
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*/
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public class Word implements Comparable<Word> {
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final String mWord;
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final int mFrequency;
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final ArrayList<WeightedString> mBigrams;
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public Word(String word, int frequency, ArrayList<WeightedString> bigrams) {
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mWord = word;
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mFrequency = frequency;
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mBigrams = bigrams;
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}
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/**
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* Three-way comparison.
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*
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* A Word x is greater than a word y if x has a higher frequency. If they have the same
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* frequency, they are sorted in lexicographic order.
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*/
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@Override
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public int compareTo(Word w) {
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if (mFrequency < w.mFrequency) return 1;
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if (mFrequency > w.mFrequency) return -1;
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return mWord.compareTo(w.mWord);
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}
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/**
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* Equality test.
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*
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* Words are equal if they have the same frequency, the same spellings, and the same
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* attributes.
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*/
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@Override
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public boolean equals(Object o) {
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if (!(o instanceof Word)) return false;
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Word w = (Word)o;
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return mFrequency == w.mFrequency && mWord.equals(w.mWord)
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&& mBigrams.equals(w.mBigrams);
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}
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}
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