LatinIME/tools/dicttool/tests/com/android/inputmethod/latin/makedict/BinaryDictEncoderFlattenTreeTests.java

50 lines
2.1 KiB
Java
Raw Normal View History

/*
* Copyright (C) 2011 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package com.android.inputmethod.latin.makedict;
import com.android.inputmethod.latin.makedict.FusionDictionary.DictionaryOptions;
import com.android.inputmethod.latin.makedict.FusionDictionary.PtNodeArray;
import junit.framework.TestCase;
import java.util.ArrayList;
import java.util.HashMap;
/**
* Unit tests for BinaryDictEncoderUtils.flattenTree().
*/
public class BinaryDictEncoderFlattenTreeTests extends TestCase {
// Test the flattened array contains the expected number of nodes, and
// that it does not contain any duplicates.
public void testFlattenNodes() {
final FusionDictionary dict = new FusionDictionary(new PtNodeArray(),
new DictionaryOptions(new HashMap<String, String>()));
dict.add("foo", new ProbabilityInfo(1), null, false /* isNotAWord */);
dict.add("fta", new ProbabilityInfo(1), null, false /* isNotAWord */);
dict.add("ftb", new ProbabilityInfo(1), null, false /* isNotAWord */);
dict.add("bar", new ProbabilityInfo(1), null, false /* isNotAWord */);
dict.add("fool", new ProbabilityInfo(1), null, false /* isNotAWord */);
final ArrayList<PtNodeArray> result =
BinaryDictEncoderUtils.flattenTree(dict.mRootNodeArray);
assertEquals(4, result.size());
while (!result.isEmpty()) {
final PtNodeArray n = result.remove(0);
assertFalse("Flattened array contained the same node twice", result.contains(n));
}
}
}