Refactor member_display_name.

Make it more readable, add comments.
master
Denis Kasak 2020-06-09 23:02:01 +02:00
parent ac069152b9
commit e4977d1d2a
1 changed files with 23 additions and 17 deletions

View File

@ -304,29 +304,35 @@ impl Room {
/// Get the disambiguated display name for a member of this room.
///
/// If a user has no display name set, returns the MXID as a fallback.
/// If a member has no display name set, returns the MXID as a fallback. Additionally, we
/// return the MXID even if there is no such member in the room.
///
/// When displaying a room member's display name, clients *must* use this method to obtain the
/// name instead of displaying the `RoomMember::display_name` directly. This is because
/// multiple users can share the same display name in which case the display name has to be
/// multiple members can share the same display name in which case the display name has to be
/// disambiguated.
pub fn member_display_name<'a>(&'a self, id: &'a UserId) -> Cow<'a, str> {
self.disambiguated_display_names
let disambiguated_name = self
.disambiguated_display_names
.get(id)
.map(|s| s.as_str().into())
.unwrap_or_else(|| {
self.members
.get(id)
.map(|member| {
member
.display_name
.as_ref()
.map(|s| s.to_string())
.unwrap_or_else(|| format!("{}", member.user_id))
.into()
})
.unwrap_or(id.as_ref().into())
})
.map(|s| s.as_str().into());
if let Some(name) = disambiguated_name {
// The display name of the member is non-unique so we return a disambiguated version.
name
} else if let Some(member) = self.members.get(id) {
// The display name of the member is unique so we can return it directly if it is set.
// If not, we return his MXID.
member
.display_name
.as_ref()
.map(|s| s.to_string())
.unwrap_or_else(|| format!("{}", member.user_id))
.into()
} else {
// There is no member with the requested MXID in the room. We still return the MXID.
id.as_ref().into()
}
}
fn add_member(&mut self, event: &MemberEvent) -> bool {